Survival of the fittest?

"If you were an alien and you knew that the planet you were watching was about to be destroyed (except for the smallest part) and you couldn't save all the inhabitants, what would you do?"

It is an interesting problem and I think the crop circles play a part in the answer.

What if, say, there were to be a coronal mass ejection from the sun on the night of 28 November (UTC) which will engulf the planet except for a tiny part measuring no more than 350 square miles?  It would be directly opposite the impact point and protected by the curvature of the planet.

It would be altruistic to save as many as possible, but that small area can only only support a limited number of people.  Who do you choose?  Answer: you don't.  You let them choose themselves.  Those who are intelligent and inquisitive will connect the crop circles, resolve the puzzle and move to the safe location indicated.  The fittest would survive.

I have an inkling that this is what has happened.  Over 50 formations I have studied suggest 28 November 2012, 53 N 0 32 W as space-time coordinates.  It was the following graphic that suggested to me what the implication could be.  It is the "Mayan Head Dress" of Wiltshire.

This is what would happen theoretically if there were a coronal mass ejection (CME) from the sun towards the Earth.  A small proportion of the planet might be exempt from the solar material.

It would seem that the artist thinks that there would be such a "safe zone".

How come 28 November 2012?  Here are my thoughts:


If the “feathers” in the head-dress are a binary code, the numbers stack up thus:
10 = 2 
100 = 4 
10 = 2 
100 = 4 
1010 = 10 
10000 = 16 
110100 = 52 (weeks in a year) 
110100 = 52 (weeks in a year) 
10000 = 16  
100 = 4 
100 = 4 
100 = 4 
100 = 4 
10 = 2

This totals 176.

These can be regarded as weeks as there are seven smaller feathers at the top of the formation.

The circle was reported 5 July 2009.  5 July 2009 + 176 weeks = 18 November 2012.

There are then ten segments apparently representing days or Maya time periods taking us to… 28 November 2012.

28 November 2012 is the 333rd day of the year, with 33 days remaining.  The three “dots” before the segments could represent 33 days to the end of the year.  On that day there is the second lunar eclipse of the year.  It is a penumbral type.  You can see that an eclipse of some type appears to be happening at the time by the crescent shapes.

There are three pairings of 'planets' that night also: Saturn with Venus, Jupiter with the Moon and Pluto with Mars.

There are seven smaller feathers on each side and 14 big ones.  14+7+7 = 28 (for 28 November), coincidentally?

There are a number of other crop formations that suggest the same thing.  I'll include them in my next posting.

In the meantime, start to check yourself for connections with 28 November 2012 and the coordinates I mentioned.

Here is an obvious example:

All the best.